8-5x-2x^2=0

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Solution for 8-5x-2x^2=0 equation: 



8-5x-2x^2=0

a = -2; b = -5; c = +8;
Δ = b2-4ac
Δ = -52-4·(-2)·8
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{89}}{2*-2}=\frac{5-\sqrt{89}}{-4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{89}}{2*-2}=\frac{5+\sqrt{89}}{-4}
$

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